C++ 求一维数组中各元素的最大值、最小值和平均值

2022-11-01 12:11发布

#include using namespace std;void process(float arr[], int len){ float

#include using namespace std;void process(float arr[], int len){ float
3条回答
2022-11-01 12:13 .采纳回答

#include<iostream>
using namespace std;
void process(float a[],int n) {

float min,max;
int i=0;
for(i=0,max=min=a[0];i<n;i++){

if(min>a[i])min=a[i];
if(max<a[i])max=a[i];

}

cout<<"\nmin="<<min;
cout<<",max="<<max<<"\n";

}
void print(float a[],int n)
{

for(int i= 0;i<n;i++) {
if(i%6==0)cout<<"\n";
cout<<a[i]<<"\t";

}

}
void main()
{
float a[24]={2,1,4,45,23,33,-7,8,5,9,0,-4,66,12,55,33,32,11,63,14,88,-9,23,6};
print(a,24);
process(a,24) ;
}本回答被提问者采纳