求函数f(x)=2x^3-6x^2-18x+1的单调区间和极值

2022-11-07 09:52发布

f(x)=6x^2-12x-18=6(x+1)(x-3)f(x)在区间(-无穷,-1)和(3,+无穷)上递增,在区间(-1,3)上递减。极大值是f(-1)=-2

f(x)=6x^2-12x-18=6(x+1)(x-3)f(x)在区间(-无穷,-1)和(3,+无穷)上递增,在区间(-1,3)上递减。极大值是f(-1)=-2