2022-11-19 03:37发布
y=x+(1-x)^(1/2)1-x≥0-1≤x≤1y=x+(1-x)^(1/2)y' = 1 - (1/2)(1-x)^(-1/2)y'=02(1-x)^(1/2) -1 =01-x =1/4x= 3/4y'|x=3/4+ <0 , y'|x=3/4- >0x=3/4 ( max)max y = y(3/4) =3/4+(1-3/4)^(1/2) =3/4 +1/2 = 5/4追问
2(1-x)^(1/2) -1 =0这部怎么来的？看不懂
y'=01 - (1/2)(1-x)^(-1/2)=0[2(1-x)^(1/2) -1]/[2(1-x)^(1/2)] =02(1-x)^(1/2) -1 =0
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y=x+(1-x)^(1/2)
追答本回答被提问者采纳1-x≥0
-1≤x≤1
y=x+(1-x)^(1/2)
y' = 1 - (1/2)(1-x)^(-1/2)
y'=0
2(1-x)^(1/2) -1 =0
1-x =1/4
x= 3/4
y'|x=3/4+ <0 , y'|x=3/4- >0
x=3/4 ( max)
max y = y(3/4) =3/4+(1-3/4)^(1/2) =3/4 +1/2 = 5/4追问
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